Roots tseem hu ua x-intercepts los yog zeros . … Yog li ntawd, kom nrhiav tau cov hauv paus hniav ntawm ib tug quadratic muaj nuj nqi, peb teem f (x)=0, thiab daws cov kab zauv, ax2 + bx + c=0.
Puas yog lub hauv paus ntawm kev sib npaug ntawm plaub npaug?
Rau qhov sib npaug ax2+bx+c=0, b2-4ac yog hu ua kev cais thiab pab txiav txim qhov xwm txheej ntawm cov hauv paus hniav ntawm ib qho kev sib npaug quadratic. Yog b2-4ac > 0, cov hauv paus hniav yog tiag tiag thiab txawv. Yog b2-4ac=0, lub hauv paus yog tiag thiab sib npaug
Puas yog cov hauv paus hniav ntawm plaub fab kev daws teeb meem?
Thaum peb daws qhov sib npaug plaub npaug peb tau txais cov kev daws hu ua cov hauv paus lossis qhov chaw qhov chaw ua haujlwm hla tus x axis.
Puas yog cov hauv paus thiab kev daws tib yam?
Txoj kev daws teeb meem ntawm kev sib npaug ntawm ntau lub npe, f(x), yog lub ntsiab lus uas nws lub hauv paus, r, yog tus nqi ntawm x thaum f(x)=0. … (-3, 0) thiab (1, 0)) yog cov kev daws teeb meem rau qhov sib npaug txij li -3 thiab 1 yog qhov tseem ceeb uas f(x)=0. Saib daim duab hauv qab no. -3 thiab 1 yog cov hauv paus.
Puas yog cov tshuaj hu ua cag?
Peb nquag siv lo lus hauv paus thaum xa mus rau cov kev daws teeb meem ntawm kev sib npaug. Piv txwv li, thaum peb muaj ib tug polynomial P(x), peb hu nws zeros lub hauv paus ntawm P(x). Rau ib co polynomials peb tuaj yeem txheeb zeros nrog lub hauv paus muaj nuj nqi ntawm qee yam, hais x2−4=0, peb tuaj yeem nqa cov hauv paus square ntawm 4 kom tau txais cov kev daws teeb meem.
