Peb feem ntau sau cov xwm txheej no rau x nyob rau ntawm kab li x=tv+a Qhov kev sib npaug no hu ua parameterization ntawm kab, qhov twg t yog qhov tsis pub dawb uas tau tso cai. ua tus lej tiag. Lub tswv yim ntawm parameterization yog tias raws li qhov parameter t sweeps los ntawm txhua tus lej tiag, x cheb tawm kab.
Koj nrhiav parameterization li cas?
Yuav kom nrhiav tau qhov parameterization, peb yuav tsum nrhiav ob vectors parallel rau lub dav hlau thiab ib qho taw tes ntawm lub dav hlau Nrhiav ib qho taw tes ntawm lub dav hlau yog ib qho yooj yim. Peb tuaj yeem xaiv tus nqi rau x thiab y thiab suav z los ntawm qhov sib npaug rau lub dav hlau. Cia x=0 thiab y=0, ces equation (1) txhais tau tias z=18−x+2y3=18−0+2(0)3=6.
Vector parameterization txhais li cas?
Txhua vector-valued muaj nuj nqi muab a parameterization ntawm ib tug nkhaus …=y (t), thiab z=z (t) uas piav qhia txog kev sib koom ua ke ntawm qhov taw tes (x, y, z) ntawm qhov nkhaus ntawm qhov ntsuas. t.
txhais tau tias yog parameterized?
"To parameterize" los ntawm nws tus kheej txhais tau tias " kom nthuav tawm cov ntsiab lus ntawm qhov tsis muaj ". Parameterization yog ib txoj kev ua lej suav nrog kev qhia txog lub xeev ntawm cov txheej txheem, txheej txheem lossis qauv raws li kev ua haujlwm ntawm qee qhov kev ywj pheej hu ua parameters.
Vector parametric equation yog dab tsi?
Cov kab zauv parametric ntawm kab yog cov khoom ntawm cov kab zauv vector, thiab muaj daim ntawv x=x0 + at, y=y0 + bt, thiab z=z0 + ct. Cov Cheebtsam a, b thiab c ntawm yog hu ua tus lej coj ntawm kab.
