Ib parameterization ntawm ib nkhaus yog a map r(t)=los ntawm parameter ncua sijhawm R=[a, b] mus rau lub dav hlau Cov haujlwm x(t), y (t) hu ua kev ua haujlwm ua haujlwm. Daim duab ntawm parametrization yog hu ua parametrized nkhaus hauv lub dav hlau. … Nws qhia piv txwv tias, peb mus raws txoj kev nkhaus sai npaum li cas.
Koj piav qhia qhov nkhaus parametric li cas?
Parametric Equations. Ib qho nkhaus hauv lub dav hlau tau hais tias yog parameterized yog tias cov txheej txheem ntawm qhov nkhaus, (x, y), yog sawv cev ua haujlwm ntawm qhov sib txawv t. Namely, x=f(t), y=g(t) t D. qhov twg D yog cov lej tiag.
Dab tsi yog qhov taw qhia ntawm parameterization?
Nyob rau hauv lej, thiab tshwj xeeb tshaj yog nyob rau hauv geometry, parameterization (los yog parameterization; kuj parameterisation, parametrisation) yog tus txheej txheem ntawm kev nrhiav parametric sib npaug ntawm ib qho nkhaus, qhov chaw, lossis, feem ntau, ib qho manifold los yog ntau yam, txhais los ntawm kev sib npaug implicit
Parameterization ntawm kab yog dab tsi?
Peb feem ntau sau cov xwm txheej no rau x nyob rau ntawm kab li x=tv+a Qhov kev sib npaug no hu ua parameterization ntawm kab, qhov twg t yog qhov tsis pub dawb uas tau tso cai. ua tus lej tiag. Lub tswv yim ntawm parameterization yog tias raws li qhov parameter t sweeps los ntawm txhua tus lej tiag, x cheb tawm kab.
Koj sau qhov parameter li cas?
Txoj kev daws teeb meem: Cov kab yog parallel rau vector v=(3, 1, 2)−(1, 0, 5)=(2, 1, −3). Li no, parameterization rau kab yog x=(1, 0, 5)+t(2, 1, −3)for−∞<t<∞. Peb kuj tuaj yeem sau qhov no li x=(1+2t,t,5−3t)for−∞<t<∞.
