Dab tsi yog Txoj Cai Tseem Ceeb? Qhov seem theorem tau teev tseg raws li nram no: Thaum ib tug polynomial a(x) muab faib los ntawm ib tug linear polynomial b(x) uas nws zero yog x=k, qhov seem yog muab los ntawm r=a(k).
Dab tsi yog qhov seem theorem Chav Kawm 9?
Txoj kev xav tseem ceeb: Cia p(x) ua ib qho polynomial ntawm degree ntau dua lossis sib npaug rau ib thiab cia tus lej tiag. Yog hais tias p(x) muab faib los ntawm linear polynomial x – a, ces qhov seem yog p(a). Pov thawj: Cia p(x) ua ib qho polynomial nrog qib siab dua lossis sib npaug rau 1.
Dab tsi yog qhov seem theorem piav qhia?
: a theorem in algebra: if f(x) is a polynomial in x then the seem ntawm kev faib f(x) by x − a is f(a)
Koj txhais li cas los ntawm qhov seem theorem?
Qhov seem theorem hais tias thaum ib tug polynomial, f(x), muab faib los ntawm ib tug linear polynomial, x - a, seem ntawm qhov kev faib yuav sib npaug rau f(a).
Dab tsi yog qhov Theorem seem nrog piv txwv?
Nws yog siv los ua kom muaj ntau lub npe ntawm txhua qhov kev kawm hauv qhov zoo nkauj. Piv txwv li: yog f(a)=a3-12a2-42 muab faib los ntawm (a-3) ces qhov quotient yuav yog a2-9a-27 thiab qhov seem yog -123. Yog li, nws txaus siab rau qhov seem theorem.
