Tshem Tawm Kev Tsis Txaus Siab. … Ib txoj haujlwm f muaj qhov tshem tawm tsis tu ncua ntawm x=a yog qhov txwv ntawm f(x) li x → muaj, tab sis yog f(a) tsis muaj, lossis tus nqi ntawm f(a) tsis sib npaug rau tus nqi txwv. Yog tias muaj qhov txwv, tab sis f(a) tsis ua, ces peb yuav pom cov duab ntawm f uas muaj "qhov" ntawm x=a.
X-tus nqi dab tsi yog qhov kev tshem tawm tsis tu ncua?
Yog tias cov haujlwm tseem ceeb thiab cov lus hauv qab tshem tawm, qhov tsis sib xws ntawm x-tus nqi uas tus denominator yog xoom yog tshem tau, yog li daim duab muaj qhov nyob hauv nws. … Yog li ntawd x + 3=0 (los yog x=–3) yog ib qho kev tshem tawm tsis tu ncua - daim duab muaj lub qhov, zoo li koj pom hauv daim duab a.
Dab tsi yog qhov tsis sib xws yog qhov ntawm X?
muaj an infinite discontinuity ntawm x=0.
Yuav ua li cas koj pom kev tshem tawm tsis tau?
Yog tias cov haujlwm tseem ceeb thiab cov lus hauv qab tshem tawm, qhov tsis sib xws ntawm x-tus nqi uas tus denominator yog xoom yog tshem tau, yog li daim duab muaj qhov nyob hauv nws. Tom qab tshem tawm, nws tso koj nrog x – 7. Yog li x + 3=0 (los yog x=–3) yog qhov tshem tawm tsis tu ncua - daim duab muaj lub qhov, zoo li koj pom hauv daim duab a.
Yog X 0 Ib qho kev tshem tawm tsis tau?
ob txoj haujlwm muaj removable discontinuities Qhov no tsis pom tseeb kiag li, tab sis peb yuav kawm tom qab ntawd: sin x 1 − cos x lim=1 thiab lim=0. ntawm cov haujlwm no muaj kev tshem tawm tsis tu ncua ntawm x=0 txawm hais tias cov feem ntau txhais tau tias lawv muaj tus lej ntawm 0 thaum x=0.
