The deBroglie wavelength yog txhais raws li nram no: lambda=h/mv, qhov twg greek tsab ntawv lambda sawv cev rau lub wavelength, h yog Planck tus contant, m yog particle qhov loj thiab v yog nws qhov nrawm.
Koj ua li cas xam tus de Broglie wavelength?
Apply the de Broglie yoj kab zauv λ=hmv λ=h m v los daws qhov wavelength ntawm cov electron txav. Kauj Ruam 3: Xav txog koj qhov txiaj ntsig. Qhov no me me wavelength yog hais txog 1/20th ntawm txoj kab uas hla ntawm hydrogen atom. Saib ntawm kab zauv, raws li qhov ceev ntawm electron txo, nws wavelength nce.
Tus qauv ntawm de Broglie kab zauv yog dab tsi?
λ=h/mv, qhov twg λ yog wavelength, h yog Planck qhov tas li, m yog qhov loj ntawm ib qho, txav ntawm qhov nrawm v. de Broglie qhia tias cov khoom tuaj yeem pom cov khoom ntawm nthwv dej.
Dab tsi yog Broglie's wavelength?
Lub de Broglie wavelength ntawm ib qho particle qhia qhov ntev ntawm cov khoom zoo li nthwv dej yog qhov tseem ceeb rau cov khoom ntawd. De Broglie wavelength feem ntau yog sawv cev los ntawm lub cim λ los yog λ dBRau ib feem nrog lub zog p, de Broglie wavelength txhais tau tias: λ dB =hp
Lambda formula yog dab tsi?
Wavelength feem ntau yog txhais los ntawm Greek tsab ntawv lambda (λ); nws yog sib npaug rau qhov ceev (v) ntawm lub tsheb ciav hlau nthwv dej hauv nruab nrab muab faib los ntawm nws qhov zaus (f): λ=v/f. …
